If a box has dimensions of 3.5 m, 6.2 m, and 1.8 m, what is its volume?

If a box has dimensions of 3.5 m, 6.2 m, and 1.8 m, what is its volume?

• A. 39.06 cubic metres
• B. 3,906 cubic metres
• C. 39.06 cubic feet
• D. 39.06 cubic centimetres

Answer: (A)

To determine the volume of a box, the formula used is length multiplied by width multiplied by height. In this case, the dimensions of the box are 3.5 meters (length), 6.2 meters (width), and 1.8 meters (height). Calculating the volume involves performing the following multiplication: Volume = Length × Width × Height Volume = 3.5 m × 6.2 m × 1.8 m Carrying out this calculation step-by-step: 1. Multiply 3.5 and 6.2 to get 21.7 m². 2. Then multiply that result, 21.7 m², by 1.8 m to get the final volume: 21.7 m² × 1.8 m = 39.06 m³. The resulting volume is therefore 39.06 cubic meters, which confirms that the choice stating 39.06 cubic metres is indeed correct. The other options reflect incorrect units or quantities that do not align with the calculated volume of the box based on its dimensions. They either misrepresent the volume through correct unit matching or scale, serving as distractors. Understanding the significance of units and correct calculation methods is

To determine the volume of a box, the formula used is length multiplied by width multiplied by height. In this case, the dimensions of the box are 3.5 meters (length), 6.2 meters (width), and 1.8 meters (height).

Calculating the volume involves performing the following multiplication:

Volume = Length × Width × Height

Volume = 3.5 m × 6.2 m × 1.8 m

Carrying out this calculation step-by-step:

1. Multiply 3.5 and 6.2 to get 21.7 m².

2. Then multiply that result, 21.7 m², by 1.8 m to get the final volume: 21.7 m² × 1.8 m = 39.06 m³.

The resulting volume is therefore 39.06 cubic meters, which confirms that the choice stating 39.06 cubic metres is indeed correct.

The other options reflect incorrect units or quantities that do not align with the calculated volume of the box based on its dimensions. They either misrepresent the volume through correct unit matching or scale, serving as distractors. Understanding the significance of units and correct calculation methods is