An object is dropped from a height of 45 m. What will its velocity be on impact?

Prepare for the ABSA 4th Class Power Engineer Certificate of Competency Exam. Study with multiple-choice questions, each with detailed explanations. Boost your confidence and ace the exam!

Multiple Choice

An object is dropped from a height of 45 m. What will its velocity be on impact?

Explanation:
To determine the velocity of an object just before impact when it is dropped from a height of 45 meters, we can use the principles of physics pertaining to free fall. When an object is dropped from a height, it accelerates towards the ground due to gravity, which is approximately 9.81 m/s² on Earth. The formula to calculate the final velocity (v) of an object falling from a certain height (h) is derived from the kinematic equation: v = √(2gh) Where: - g = acceleration due to gravity (approximately 9.81 m/s²) - h = height from which the object is dropped (in this case, 45 m) Plugging in the values: v = √(2 * 9.81 m/s² * 45 m) v = √(882.9 m²/s²) v ≈ 29.71 m/s Thus, the velocity of the object when it impacts the ground would be approximately 29.71 m/s. This aligns with the fundamental principles of caused motion, establishing a clear understanding of how objects accelerate under gravity, leading to the conclusion that the correct answer is based on standard gravitational effects on falling bodies.

To determine the velocity of an object just before impact when it is dropped from a height of 45 meters, we can use the principles of physics pertaining to free fall. When an object is dropped from a height, it accelerates towards the ground due to gravity, which is approximately 9.81 m/s² on Earth.

The formula to calculate the final velocity (v) of an object falling from a certain height (h) is derived from the kinematic equation:

v = √(2gh)

Where:

  • g = acceleration due to gravity (approximately 9.81 m/s²)

  • h = height from which the object is dropped (in this case, 45 m)

Plugging in the values:

v = √(2 * 9.81 m/s² * 45 m)

v = √(882.9 m²/s²)

v ≈ 29.71 m/s

Thus, the velocity of the object when it impacts the ground would be approximately 29.71 m/s. This aligns with the fundamental principles of caused motion, establishing a clear understanding of how objects accelerate under gravity, leading to the conclusion that the correct answer is based on standard gravitational effects on falling bodies.

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